34.(C) Codeforces 791 A--->>>Bear and big brother

 #include<stdio.h>

// #Tricky --->>

/*Bear Limak wants to become the largest of bears,

 or at least to become larger than his brother Bob.

Right now, Limak and Bob weigh a and b respectively.

 It's guaranteed that Limak's weight is smaller than or

  equal to his brother's weight.

Limak eats a lot and his weight is tripled after every

year, while Bob's weight is doubled after every year.

After how many full years will Limak become strictly

larger (strictly heavier) than Bob?

Input

The only line of the input contains two

 integers a and b (1 ≤ a ≤ b ≤ 10) — the weight of Limak and the weight of Bob respectively.

Output

Print one integer, denoting the integer number of years

 after which Limak will become strictly larger than Bob.

Examples

input

4 7

output

2

input

4 9

output

3

input

1 1

output

1

Note

In the first sample, Limak weighs 4 and Bob weighs 7

initially. After one year their weights are 4·3 = 12 and 7·

2 = 14 respectively (one weight is tripled while

the other one is doubled). Limak isn't larger than Bob yet.

After the second year weights are 36 and 28,

so the first weight is greater than the second one.

Limak became larger than Bob after two years so you should

 print 2.

In the second sample, Limak's and Bob's weights

in next years are: 12 and 18, then 36 and 36,

and finally 108 and 72 (after three years).

The answer is 3. Remember that Limak wants to be larger

than Bob and he won't be satisfied with equal weights.

In the third sample, Limak becomes larger than Bob after

 the first year. Their weights will be 3 and 2 then.

*/

int main(){

    int a,b,y=0;

    scanf("%d %d",&a,&b);

    while(1) // active the loop for infinite time

    {

        y++;

        a=a*3; // it will first test

the condition whether it's true

or not .If it is true then

it will left the loop but the value

of y will increase.

        b=b*2;

        if (a>b)

        {

            printf("%d",y);

            break;

        }

    }

    return 0;

}